Car A Averages 8 Km Per Liter Of Fuel. Car B Averages 12 Km Per Liter Of Fuel. If The Price Of Fuel Is $10 Per Liter. How Much Less, Would A 600 - Km.
Car A averages 8 km per liter of fuel. Car B averages 12 km per liter of fuel. If the price of fuel is $10 per liter. How much less
would a 600 - km. trip cost for Car A than for Car B?
Answer:
The difference in fuel cost is $250.
Step-by-step explanation:
Cost per liter: $10
Car A:
Average fuel consumption = 8 km/liter
For every 8 km, Car A consumes 1 liter.
Distance traveled: 600 km
Cost = (600 km/8 km) × $10
Cost = 75 x $10
Cost = $750
Car B:
Average fuel consumption: 12 km/liter
For every 12 km, Car B consumes 1 liter.
Distance traveled: 600 km
Cost = (600 km/12 km) × $10
Cost = 50 × $10
Cost = $500
The question should be:
How much more would a 600-km trip cost for Car A than for Car B?
or
How much less would a 600-km trip cost for Car B than for Car A?
In both cases, we solve for the difference in fuel cost between the two cars.
Solution:
Fuel cost difference = Car A - Car B
Fuel cost difference = $750 - $500
Fuel cost difference = $250
Conclusion:
Car B is more efficient in terms of fuel consumption and cost.
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