Car A Averages 8 Km Per Liter Of Fuel. Car B Averages 12 Km Per Liter Of Fuel. If The Price Of Fuel Is $10 Per Liter. How Much Less, Would A 600 - Km.

Car A averages 8 km per liter of fuel. Car B averages 12 km per liter of fuel. If the price of fuel is $10 per liter. How much less

would a 600 - km. trip cost for Car A than for Car B?

 

Answer:

The difference in fuel cost is $250.

Step-by-step explanation:

Cost per liter: $10

Car A:

Average fuel consumption = 8 km/liter

For every 8 km, Car A consumes 1 liter.

Distance traveled: 600 km

Cost = (600 km/8 km) × $10

Cost = 75 x $10

Cost = $750

Car B:

Average fuel consumption: 12 km/liter

For every 12 km, Car B consumes 1 liter.

Distance traveled: 600 km

Cost =  (600 km/12 km) × $10

Cost = 50 × $10

Cost = $500

The question should be:

How much more would a 600-km trip cost for Car A than for  Car B?

or

How much less would a 600-km trip cost for Car B than for Car A?

In both cases, we solve for the difference in fuel cost between the two cars.

Solution:

Fuel cost difference = Car A - Car B

Fuel cost difference = $750 - $500

Fuel cost difference = $250

Conclusion:

Car B is more efficient in terms of fuel consumption and cost.